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An arc lamp requires a direct current of 10 A at 80 V to function. If it is connected to a 220 V (rms), 50 Hz AC supply, the series inductor needed for it to work is closed to: |
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Answer» 80 H Now, `I=V_(rms)/"|z|"` (For A.C. current ) `10=220 /sqrt(R^2+X_L^2)` `100=(220xx220)/((8)^2+X_L^2)` `64+X_L^2=484` `therefore X_L^2`= 420 `therefore X_L = sqrt420` `therefore 2pif L=sqrt420` `therefore 2xx3.14xx50xxL = sqrt420` 314 L = `sqrt420` `therefore L=20.49/314` `therefore` L=0.6526 `APPROX` 0.065 H |
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