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An artificial satellite is moving in a circular orbit around the earth, with a speed which is equal to half the magnitude of the escape velocity from the earth. What is the height of the satellite above the surface of the earth ?A. 2 RB. RC. `(R )/(2)`D. `(R )/(4)` |
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Answer» Correct Answer - B It is given that `v_(0)=(1)/(2)v_(e )` `therefore ((GM)/(R+h))=(1)/(2)sqrt((2GM)/(R ))` `therefore (GM)/(R+h)=(1)/(4).(2GM)/(R )=(GM)/(2R)` `therefore 2R=R+h " " therefore h = R` |
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