InterviewSolution
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InterviewSolution
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An assembly of smoke particle in air at `NTP` is under consideration. If the mass of each particles is `5 xx 10^(-17) kg`. Then the rms speed is (Given: `k = 1.38 xx 19^(-23) J K^(-1)`) |
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Answer» Here, `m= 5 xx 10^(-17) kg , k=1.38 xx 10^(-23) J//K`. `T=0^(@)C = (0+273)K 273 K, upsilon_(rms) = ?` `upsilon_(rms) = sqrt((3RT)/(M)) = sqrt((3kNT)/(mN)) =sqrt((3kT)/(m))` `= sqrt((3xx 1.38 xx 10^(-23) xx 273)/(5 xx 10^(-17)))` `upsilon_(rms) = 1.5 xx 10^(-2) m//s = 1.5 cm//s`. |
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