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An asteroid of mass `m` is approaching earth, initially at a distance `10R_(E)` with speed `v_(i)`. It hits earth with a speed `v_(f)` (`R_(E)` and `M_(E)` are radius and mass of earth),. ThenA. `v_(f)^(2)=v_(i)^(2)+(2Gm)/(M_(e)R)(1-1/10)`B. `v_(f)^(2)=v_(i)^(2)+(2Gm_(e))/(R_(e))(1+1/10)`C. `v_(f)^(2)=v_(i)^(2)+(2Gm_(e))/(R_(e))(1-1/10)`D. `v_(f)^(2)=v_(i)^(2)+(2Gm)/(R_(e))(1-1/10)` |
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Answer» Correct Answer - C `1/2mv_(i)^(2)-(GM_(e)m)/((10 R_(e)))=1/2mv_(f)^(2)-(GM_(e)m)/(( R_(e)))` `v_(f)^(2)=v_(i)^(2)+(2GM_(e))/(R_(e))(1-1/10)` |
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