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an athelete completes 1 round of a circular track of diameter 4oo m in 80 sec what will be the distance covered and the displacement at end of 4 min 40 sec |
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Answer» The total distance covered for one complete ROUND = parameter of a CIRCULAR track with a diameter 400 m = πd, ((22/7) * 400)Time taken to complete one round = 80 sec4 min 40 sec = 280 sec i.e (240 + 40) = 3 complete rounds and 40 seconds= 3 complete rounds + 0.5 round = 3.5 roundsTotal distance covered = ((22/7)*400)*(7/2) = 4,400 mdisplacement = shortest distance from origin = exact diameter distance.so it will be 400 |
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