1.

An atom of an element hasthe electrons distributedin four shells . If the electrons present in I and IV shells is in1:1ration and , the ratio of electrons in II and IIIshell is also1:1, predict its valency and justofy .Write the formulaeof (a) nitride (b) silicate (c ) chloride.

Answer»

Solution :`{:(K,L_(,),M,N),(2_(,),8,8,2):}`
Hence the valency of an ATOM of an element (M) with above electronic CONFIGURATION is 2 andby losing twoelectrons it attains octetconfiguration.
(a)Formula of its nitride is`M^(+2)N^(-3)toM_(3)N_(3)`
(b)Formula of its silicate is`M^(+2)SiO3^(-2)toMSiO_(3)`
( C)Formula of its chloride is `M^(+2)Cl^(-)toMCl_(2)`


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