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An atom of an element hasthe electrons distributedin four shells . If the electrons present in I and IV shells is in1:1ration and , the ratio of electrons in II and IIIshell is also1:1, predict its valency and justofy .Write the formulaeof (a) nitride (b) silicate (c ) chloride. |
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Answer» Solution :`{:(K,L_(,),M,N),(2_(,),8,8,2):}` Hence the valency of an ATOM of an element (M) with above electronic CONFIGURATION is 2 andby losing twoelectrons it attains octetconfiguration. (a)Formula of its nitride is`M^(+2)N^(-3)toM_(3)N_(3)` (b)Formula of its silicate is`M^(+2)SiO3^(-2)toMSiO_(3)` ( C)Formula of its chloride is `M^(+2)Cl^(-)toMCl_(2)` |
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