An atom possesing the total angular momentum ` ħvv6` is in the state with spin quantum number `S=1`. In the corresponding vector model the angle between the spin momentum and the total angular momentum is `theta= 73.2^(@)`.Write the spectral symbol for the term that state.

An atom possesing the total angular momentum ` ħvv6` is in the state

1.	An atom possesing the total angular momentum ` ħvv6` is in the state with spin quantum number `S=1`. In the corresponding vector model the angle between the spin momentum and the total angular momentum is `theta= 73.2^(@)`.Write the spectral symbol for the term that state.
Answer» Total angular momentum ` ħsqrt(6)` means `J=2`. It is gives that `S=1` This means that `L=1,2 or 3`. From vector model relation `L(L+1) ħ^(2)=6 ħ^(2)+2 ħ^(2)sqrt(6)sqrt(2) cos 73.2^(@)` `=5.998 ħ^(2)~~6 ħ^(2)` Thus `L=2` and the spectral symbol of the state is `.^(3)D_(2)`

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An atom possesing the total angular momentum ` ħvv6` is in the state with spin quantum number `S=1`. In the corresponding vector model the angle between the spin momentum and the total angular momentum is `theta= 73.2^(@)`.Write the spectral symbol for the term that state.

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