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An automobile engine develops a power of 100 Killowalt, when rotating at a speed of 30 rev/sec. What torque does it deliver ? |
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Answer» Solution :In translation MOTION `P=Fxxv` in rotational motion` P=to U OMEGA` `THEREFORE` to `u=P//omega =(100xx1000)//(2pixx30)=5000//pi` |
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