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An automobile of mass m accelerates from rest. If the engine supplies a constant power P, the velocity at time t is given by -A. `(2Pt)/(M)`B. `sqrt((2Pt)/(m))`C. `(Pt)/(2M)`D. `sqrt((Pt)/(2 M))` |
Answer» Correct Answer - B (b) We have, P=Fv=constant (given) `rArr M((dv)/(dt))v=P" or ""vdv"=(Pdt)/(M)` Integrating both side, we get `(v^(2))/(2)=(P)/(M)t" or "v=sqrt((2Pt)/(M))` |
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