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An average induced e.m.f. of 1 V appears in coil when the current in it is changed from 10 A in one direction to 10 A in opposite direction in 0.5 sec. Self inductance of the coil is |
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Answer» Solution :Magnitude of `e=L.(dI)/(dt)` `rArr e=L.([10-(-10)])/(0.5)=L xx (20)/(0.5)=L xx 40` `rArr 1= L xx 40 rArr L = (1)/(40)=0.025 H = 25 mH` |
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