1.

An average induced e.m.f. of 2V appears in a coil when the current in it is changed from 10A in one direction to 10A in opposite direction in 0.5sec. What is the self inductance of the coil?

Answer»

SOLUTION :`E = L(dI)/DT = L(20/0.5) = 40L `
`therefore L = 2/20 = 1/20 = 0.05H = 50mH`.


Discussion

No Comment Found

Related InterviewSolutions