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An average induced e.m.f. of 2V appears in a coil when the current in it is changed from 10A in one direction to 10A in opposite direction in 0.5sec. What is the self inductance of the coil? |
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Answer» SOLUTION :`E = L(dI)/DT = L(20/0.5) = 40L ` `therefore L = 2/20 = 1/20 = 0.05H = 50mH`. |
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