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An average-reading digital Multimeter reads 10 V when fed with a triangular wave, symmetric about the time-axis. If the input is same, the rms reading meter will read?(a) 20/\(\sqrt{3}\)(b) -10/\(\sqrt{3}\)(c) -20/\(\sqrt{3}\)(d) 10/\(\sqrt{3}\)The question was posed to me in final exam.My question is from Advanced Miscellaneous Problems on Measurement of Power topic in chapter Measurement of Power and Related Parameters of Electrical Measurements

Answer»

Right ANSWER is (d) 10/\(\SQRT{3}\)

To EXPLAIN I WOULD say: For triangular WAVE- Average value = \(\frac{V_m}{3}\), rms value = \(\frac{V_m}{\sqrt{3}}\)

\(\frac{V_m}{3}\) = 10 V or, Vm = 30 V

So, rms = \(\frac{30}{\sqrt{3}}\) = 10\(\sqrt{3}\).


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