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An e.m.f. of 40mV is induced in a solenoid when the current in it changes at the rate of 2A/s. What is the self-inductance of solenoid? |
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Answer» SOLUTION :`e = L(dI)/dt ` `THEREFORE 40xx10^-3 = Lxx2` ` therefore L = 20xx10^-3H` = 20mH. |
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