1.

An e.m.f. of 40mV is induced in a solenoid when the current in it changes at the rate of 2A/s. What is the self-inductance of solenoid?

Answer»

SOLUTION :`e = L(dI)/dt `
`THEREFORE 40xx10^-3 = Lxx2`
` therefore L = 20xx10^-3H` = 20mH.


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