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An e.m. wave trevelling along z -axis: vecE=vecE_0cos (kz-omegat). Choose the correct option from the following : |
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Answer» The associated magnetic FIELD is given as `vecB=1/C hatkxxvecE` `vecE=vecE_0cos (kz-omegat)` which is perpendicular to z-axis. It acts along negative y-direction. The associated magnetic field `vecB` in em wave is along x-axis, i.e., along `hatkxxvecE`. As `B_0=(E_0)/c :. vecB=1/c(hatkxxvecE)` Thus, option (a) is correct. The associated electric field can be written in terms of magnetic field as `vecE=c(vecBxxhatk)` Thus, option (b) is correct. Angle between `hatk and vecE` is `90^@`. THEREFORE, `hatk. vecE=1Ecos 90^@=0` and `hatk.vecB=1vecEcos 90^@=0.` Thus, option (c) is correct. |
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