1.

An echo repeats two syllables. If the velocity of sound is 330 m/s. then the distance of reflecting surface is :

Answer»

16.5 m
33.0 m
66 m
99 m

Solution :A man can SPEAK 5 syllable in 1 sec.
`therefore ` TIME TAKEN to speak disyllable = `(2)/(5) `sec
If d is the distance of reflector then.
` t = (2 d)/(V) `
`(2)/(5) = (2d)/(330)`
`rArr "" d = 66 m `
Hence the corret choice is (C).


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