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An elastic cord having an upstretched length l, force constant k and mass per unit length m_(@) is stretched arouond the drum of radius (2pirgtl) Determine the speed of the cord, due to rotation of te drum, which will allow the cord to loosen its contact with the drum. Express value of (v^(2))/11 (in m^(2)//s^(2)) ( for the given data m_(0)=40g//cm, k=100N/m, pi=22/7, l=400cm, r=70cm)

Answer»


SOLUTION :`V=sqrt((k(/_\x)2piR)/(m_(@)l)), k/_\x=T`
`2T"sin" ((d theta)/2)=(dm)(v^(2))/R`
or `T(2pi)=m (v^(2))/R`
`(k/_\x)2pi(m_(@)l)(v^(2))/R`
`v=(sqrt(k(/_\x)2piR)/(m_(@)l))` & `/_\x=(2pir-I)`


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