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An electicdipoleplacedin vacuumis formedby twoequalbutopposite charges each of magnitude1mu Cseparatedby a distance of 2 cm. calculatethe electric fieldintensities in thefollowingcases :(i)ata pointon theaxisof thedipole situatedata distance60 cmaway from itscentre. (ii)ata pointon theperpendicularbisector ofthedipolesituatedat a distance60cmawayfrom itscentre. |
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Answer» SOLUTION :Moment of the electricdipole, ` p = q * 2l = 1 xx 10 ^(-6)xx 2 xx 10 ^( -2 )= 2 xx10^(- 8 ) C *m ` (i) Electricfieldintensity on theaxisof the dipole, `E _ 1=( 1 ) /( 4piin _0)*( 2p ) /( R ^ 3 )=( 9 xx 10 ^ 9xx 2 xx 2 xx 10 ^( - 8)) /( (0 .6) ^3 ) ` ` = 1666.6 N *C^( -1 )` ,ALONGTHE axis (ii)Electricfieldintensity on the perpendicularbisector of the dipole, `E _ 2=( 1 ) /( 4pi in _0 )* (p ) /(r ^ 3)=( 1 )/( 2 )E _ 1 ` ` = 833.3 N*C ^ (-1 )` ,parallelto axisof thedipole |
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