1.

An electric charge is placed at the centre of a cube of side a. The electric flux through one of its foces will be

Answer»

`(q)/(6 epsilon_(0))`
`(q)/(epsilon_(0)a^(2))`
`(q)/(4 PI epsilon_(0) a^(2))`
`(q)/(epsilon_(0))`

Solution :According to Gauss.s law, the electric flux through the cube is `(q)/(epsilon_(0))`. Since there are six FACES, the flux through one face is `(q)/(6 epsilon_(0))`.


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