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An electric dipole is at 30° with uniform electric field of 2 xx 10^(5) N/C. The torque acting on it is 4 Nm. If length of dipole is 2 cm, then what will be the charge at one end of dipole ? |
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Answer» 5 MC `tau=q(2a)Esintheta` `THEREFORE q=tau/(2a xx Esintheta)` `=4/(2 xx 10^(-2) xx 2 xx 10^(5) xx sin 30^(@))` `=1/(10^(3) xx 1/2)` `=1/500 = 0.002 C = 2 xx 10^(-3) C = 2mC` |
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