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An electric dipole is placed at an angle of `30^(@)` with an electric field intensity `2xx10^(5)N//C`. It experiences a torque equal to `4Nm`. The charge on the dipole, if the dipole is length is `2 cm`, isA. `5 mC`B. `7muC`C. `8mC`D. `2 mC` |
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Answer» Correct Answer - d `tau=PE sin theta` `tau=ql E sin theta` `4= qxx2xx10^(-2)xx2xx10^(5) sin 30^(@)` `implies q= 2mC` |
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