InterviewSolution
Saved Bookmarks
| 1. |
An electric field E is present perpendicular to a square plate of side length L. What is the flux passing through the plate?(a) LE(b) L^2E(c) \(\frac {L^2}{E}\)(d) ZeroThe question was posed to me by my college professor while I was bunking the class.The query is from Gauss’s Law in section Charges and Fields of Physics – Class 12 |
|
Answer» RIGHT option is (b) L^2E Best explanation: We KNOW that electric flux is equal to the product of the electric field and the surface AREA of a surface. In this CASE, the plate has surface area L*L = L^2 and hence the net flux passing through the surface is = L^2E. |
|