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An electric field is described by the field lines as shown. Explain about the nature of the field. |
Answer» Solution :Considera closed path p q r as shown in the given field At pq field intensity is `E_(1)` and at rs field intensity is `E_(2)`. From the given distribution of field lines `E_(2) gt E_(1)`. Field is perpendicular to QR or ps Now `OINT BARE. d barl=int E_(1)(pq) +intE_(2)(sr)` `=(E_(1)-E_(2))pq NE 0` (`:. int barE. d barl=0` for qr and ps) Line integral of `barE. dbarl` alongclosed pathis nonzero in this CASE. But we know that electric field is conservative and `oint barE.d barl=0`. It means electric field as shown in not possible. |
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