An electric field is given as E = 6y^2z i + 12xyz j + 6xy^2 k. An incremental path is given by dl = -3 i + 5 j – 2 k mm. The work done in moving a 2mC charge along the path if the location of the path is at p(0,2,5) is (in Joule)(a) 0.64(b) 0.72(c) 0.78(d) 0.80The question was asked by my school teacher while I was bunking the class.This question is from Line Integral topic in section Vector Calculus of Electromagnetic Theory

An electric field is given as E = 6y^2z i + 12xyz j + 6xy^2 k. An incr

1.	An electric field is given as E = 6y^2z i + 12xyz j + 6xy^2 k. An incremental path is given by dl = -3 i + 5 j – 2 k mm. The work done in moving a 2mC charge along the path if the location of the path is at p(0,2,5) is (in Joule)(a) 0.64(b) 0.72(c) 0.78(d) 0.80The question was asked by my school teacher while I was bunking the class.This question is from Line Integral topic in section Vector Calculus of Electromagnetic Theory
Answer» The correct option is (b) 0.72 Easy explanation: W = -Q E.dl W = -2 X 10^-3 X (6y^2z i + 12xyz j + 6xy^2 K) . (-3 i + 5 j -2 k) At p(0,2,5), W = -2(-18.22.5) X 10^-3 = 0.72 J.

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