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An electric field is represented by vecE= "Ax" hati where A = 10 (V)/(m^(2)) . Find the potential of the origin with respect to the point (10,20) m. |
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Answer» <P> Solution :Here `vecE = "Ax" hati= 10 X hati`coordinates of origin = (0,0) m Suppose corrdinates P in the field = (10,20) m `V(0,0) - V(10,20) = - int_(((10,20)))^(((0,0)))vecE.vec(d)r` =- `int_(((10,20)))^(((0,0))) 10X hati . ( dx hati+ dy hatj)` `:. V(0,0)= -int_(10)^(0) 10 x.dx [ because V(10, 20) =0]` `=-10 [(x^(2))/(2)]_(10)^(0)` `:. V(0,0) = 500 V ` |
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