1.

An electric field of strength E = 1.0 kV//cm produces plarization in waterequivalent to the correctorientation of onlyone outof N . The electric moment of a water molecule equals p = 0.62.10^(-29) C.m.

Answer»

Solution :The TOTAL polarization is `P = (E - 1) epsilon_(0) E`. This must equals`(n_(0) p)/(N)` where `n_(0)` is the concertaition of water molecules. Thus
`N = (n_(0) P)/((e - 1) epsilon_(0) E) = 2.93xx10^(3)` on putting the values


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