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An electric lamp which runs at 40 V consumes 10 A current is connected to AC mains at 100 V,50 cycles per second. Calculate the inductance of the choke. |
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Answer» Solution : Data supplied, I = 10 A, V= 40 V, E= 100 V, f=50 Hz, `OMEGA = 2pi f= 100 pi ` `I = (E )/(SQRT(R^2 + omega^2 t^2) )` ` 10 = (100)/(sqrt(16+ (100 pi L)^2)` solving we get ` sqrt(16 + (10 pi L)^2)= 10` `16 + (100 pi L)^2 = 100` `L = 0.02916 H` |
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