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An electrical technicanrequiresa capacitance fo 2 muF in a circuit across a potential difference of 1kV. A large number 1muF capacitor are available to him each of which can withstand a potential difference of not more than 400V. Suggest a possible arrangement that requires the minimum number of capacitors. |
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Answer» Solution :`C_("eff")=2muF= 2 xx 10^(-6)F ""V=1kV=10^(3)V""C=1muF=10^(-6)F," rate 400V"` Total change, `Q=C_("eff") V=2 xx 10^(-6) xx 10^(3)=2 xx 10^(3) C` Let there be .n. capacitors in series and m such rows in the circuit. Effective capacity, `C_("eff")=C/n xx m` `2 xx 10^(-6) =(10^(-6)m)/(n)"m=2N"` Also `(1000)/(n) LT 400 "i.e,"=(10)/n lt 4` `5/n lt 2 or 2n lt 5, n gt 2.5 i.e, " 3Hence m=6"` |
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