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An electrical technician requires a capacitance,of 2 muFin a circuit across a potential difference of 1 kV. A large number of1 muFcapacitors are available to him each of which can withstand a potential difference of more than 400 V. Suggest a possible arrangementthat requires the minimum number of capacitors . |
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Answer» Solution :For obtain 2 `mu`F capacitance and p.d. of 1 kVnumber of capacitor connected in series of `1mu`capacitor and such m series connected i parallel For number of capacitor in each row is GIVEN a `p.d. = (V)/(n) = (1000)/(n)` `400 = (1000)/(n)` `:. n = (1000)/(400) ` `:. n = 2.5` but no. of capacitor should be in integer `:. ` n =3 The equivalent of capacitance of composition connection , `(m)/(n) = 2 IMPLIES m=2n` = `2xx3` =6 Required number of capacitor = MN `= 6xx3` = 18 This composite connection is shown as figure 
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