1.

An electromagnetic wave is travelling in x-direction with electric field vector given by, vecE_(y) = E_(0) sin (kx – omegat) hatj. The correct expression for magnetic field vector is

Answer»

`vecB_(y) = (E_(0))/(C) sin(kx - omegat)hatj`
`vecB_(y) = E_(0)C sin(kx - omegat)hatj`
`vecB_(z) = (E_(0))/(C) sin(kx - omegat)HATK`
`vecB_(z) = E_(0)C sin(kx - omegat)hatk`

Solution :(c): `(E_(0))/(B_(0)) = rArr B_(0) = (E_(0))/C`
The DIRECTION of magnetic FIELD must be TOWARDS z-axis.


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