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An electromagnetic wave of v = 3MHz passes from vacuum into dielectric medium with epsilon = 4.0 epsilon_(0). Then :

Answer»

wavelength is doubled and FREQUENCY BECOMES half
wavelength is doubled and freq. is same.
wavelength and frequency both remain unchanged.
wavelength is halved but frequency remains same.

Solution :`C=(1)/(sqrt(mu_(0)epsilon_(0))), C. =(1)/(sqrt(mu_(0)4epsilon_(0)))=(1)/(2)C`
`:. C=v lambda implies C PROP lambda` so when `C. =C // 2, lambda.=lambda // 2`


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