1.

An electron accelerated under a potential difference V volt has a certain wavelength lamda. Mass of the proton is 2000 times the mass of the electron. If the proton has to have the same wavelength lamda, then it will have to be accelerated under a potential difference of:

Answer»

V volt
2000 V volt
`(V)/(2000)` volt
`SQRT(2000)` V volt.

Solution :`LAMBDA=(H)/(sqrt(2meV))`, here `mv=cost`
`:.200xxV.=V xx 1 rArr V.=(V)/(2000)` Volt


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