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An electron, an alpha-particle and a proton have the same kinetic energy. Which one of these particles has the largest de-Broglie wavelength ?

Answer»

SOLUTION :As `lamda=(h)/(sqrt((2mK)))` and KINETIC enerrgy is CONSTANT, hence `lamdaprop(1)/(sqrtm)` i.e., ELECTRON particle, being lightest, will have the LARGEST de-Broglie wavelength.


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