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An electron and a photon each have a wavelength 1.00 nm. Find (i) their momenta, (ii) the energy of the photon and (iii) the kinetic energy of electron. |
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Answer» Given, `lambda = 1 mm = 10^(-9)m, h = 6.63xx10^(-34)J - s, c = 3xx10^(8)m//s` `E_(ph)=(hc)/(lambda)=(6.63xx10^(-34)xx3xx10^(8))/(10^(-9)xx1.6xx10^(-19))eV = 1243 eV therefore E_(ph) = 1.243 KeV`. |
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