InterviewSolution
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InterviewSolution
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An electron and a photon each have a wavelength of 1.00 nm. Find (a) their momenta, (b) the energy of the photon, and (c) the kinetic energy of electron. |
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Answer» Solution :Here `lamda=1.00nm=1.00xx10^(-9)m` (a) Momentum of electron momentum of photon `p=(h)/(lamda)=(6.63xx10^(-34))/(1.00xx10^(-9))=6.63xx10^(-25)KG" "MS^(-1)`. (B) Energy of photon `E=(HC)/(lamda)p*c=6.63xx10^(-25)xx3xx10^(8)=1.989xx10^(-16)J` `=(1.989xx10^(-16))/(1.6xx10^(-19))eV=1.24xx10^(3)eV or 1.24keV`. (c) Kinetic energy of electron `K=(p^(2))/(2m)=((6.63xx10^(-25))^(2))/(2xx9.11xx10^(-31))=2.413xx10^(-19)J` `=(2.413xx10^(-19))/(1.6xx10^(-19))eV=1.51eV`. |
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