An electron and a proton with equal momentum enter perpendicularly into a uniform magnetic field, thenA. path of both will be straight lineB. both are equally curvedC. the path of proton shall be less curved than that of electronD. the path of proton shall be less curved than that of electron

An electron and a proton with equal momentum enter perpendicularly int

1.	An electron and a proton with equal momentum enter perpendicularly into a uniform magnetic field, thenA. path of both will be straight lineB. both are equally curvedC. the path of proton shall be less curved than that of electronD. the path of proton shall be less curved than that of electron
Answer» Correct Answer - B The radius of circular path traced by electron and proton is given by `r=(mv)/(qB)=(p)/(qB)=sqrt(2mKE)/(qB)` `therefore r prop v prop p prop sqrt(k)` As both proton and electron have same momentum hence both will have the same circular path i.e both are equally curved

Discussion

No Comment Found

Related InterviewSolutions

When a current carrying coil is placed in a uniform magnetic field of induction `B`, then a torque `tau` acts on it. If `I` is the current, `n` is the number of turns and `A` is the face area of the coil and the normal to the coil makes an angle `theta` with `B`, ThenA. `tau= n I AB`B. `tau= n I AB cos theta`C. `tau = n I AB sin theta`D. `tau = n I AB tan theta`
The magnetic induction at apoint P which is at the distance 4 cm from a long current carrying wire is `10^(-3) T`. The field of induction at a distance 12 cm from the current will beA. `3.33xx10^(-9)`teslaB. `1.11xx10^(-4)` teslaC. `3xx10^(-3)` teslaD. `9xx10^(-2)` tesla
The field due to a long straight wire carrying a current I is proportional toA. IB. `sqrt(I)`C. `I^2`D. `1//I`
In cyclotron for a given magnet radius of the semicircle traced by positive ion is directly proportional to (where v= velocity of positive ion)A. `v^-2`B. `v^-1`C. `v`D. `v^2`
The voltage sensitvity of M.C.G. is given byA. `S=(n AB)/(K)`B. `S=(n AB)/(KG)`C. `S= n ABKG`D. `S=(KG)/(n AB)`
A straight wire of length 1 m, and carrying a current of 1.8 A, is placed in a uniform magnetic field of induction 2T. If the magntic field is perpendicular to the length of the wire, then the force acting on the wire isA. 1.8 NB. 3.6NC. 0.9ND. 2.5N
The maximum velocity to which a proton can be accelerated in a cyclotron of 10 MHZ frequency and radius 50 cm isA. `6.28xx10^(8) ms^(-1)`B. `3.14xx10^(8) ms^(-1)`C. `6.28xx10^(7) ms^(-1)`D. `3.14 xx10^(7) ms^(-1)`
If the radius of the dees of cyclotron is r then the kinetic energy of a proton of mass m accelerated by the cycloton at an oscillating frequency v isA. `4pi^(2)m^(2)v^(2)r^(2)`B. `4pi^(2)mv^(2)r^(2)`C. `2pi^(2)mv^(2)r^(2)`D. `pi^(2)mv^(2)r^(2)`
In a cyclotron, the angular frequency of a charged particle is independentA. massB. speedC. chargeD. magnetic field
In a cyclotron, the charged particle cannot be accelerated to energies of the order of billion electron volt because if the speed of the particle is increasedA. the frequency of revolution is increasedB. the frequency of revolution is decreasedC. the frequency of a.c. source is decreasedD. the frequecny of a.c. source is increased

An electron and a proton with equal momentum enter perpendicularly into a uniform magnetic field, thenA. path of both will be straight lineB. both are equally curvedC. the path of proton shall be less curved than that of electronD. the path of proton shall be less curved than that of electron

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment