1.

An electron beam passes through a magnetic field of2xx10^(-3) T and electric field of 3xx10^(-4) V/m at right angles to it. Its specific charge is 1.75xx10^(11)C//kg^(-1). What is the radius of the path in which it is deflected, if there is no deflection, when both fields are acting ?

Answer»

0.43 m
4.3 cm
0.43 cm
none of the above.

Solution :`v=(E)/(B)=(3XX10^(4))/(2xx10^(-3))=1*5xx10^(7) ms^(-1)`
Also `BeV=(mv^(2))/(r) or v=(Ber)/(m)`
or `r=(mv)/(Be)=(1.5xx10^(7))/(2xx10^(-3)xx1*75xx10^(11))`
`=(1500)/(200)xx(1)/(175)=(15)/(350)XX100 cm=(30)/(7) cm=4*3 cm`


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