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An electron in a circular orbit of radius 0.05 mm performs 10^(16) revolutions per second. The magnetic moment due to this rotation of electron is ("in Am"^(2)) |
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Answer» `2.16 xx 10^(-23)` `= 0.05 xx 10^(-9)m` Frequency, `v = 10^(16)rev//s` The electron moving in a orbit behaves as a CURRENT loop. The current due to orbit MOTION of electron is `I = ev` Area of the loop, `A = pir^(2)` `therefore` Magnetic moment of the loop, `M = IA = evpur^(2)` `therefore M = 1.6 xx 10^(-19) xx 10^(16) xx 3.14 xx (0.05 xx 10^(-9))^(2)` `= 0.0126 xx 10^(-21) Am^(2) = 1.26 xx 10^(-23)A m^(2)` |
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