Saved Bookmarks
| 1. |
An electron in a hydrogen atom is in an excited state and corresponding principal quantum number is n. Obtain the expression for orbital magnetic moment of electron. Charge on electron is e, mass of electron is m. |
|
Answer» Solution :Let R be the radius of orbit. We can WRITE angular momentum of electron as FOLLOWS: `mvR = (nh)/(2 pi)` Where h is Planck.s constant. ` v = (nh)/(2 pi mR) ` …(i) Equivalent current due to electron can be written as follows: ` I = e/T = e/(2 pi R //v) = (ev)/(2 pi R)` SUBSTITUTING the value of u in equation (i) we get the following: ` I = (e(nh)/(2 pi mR))/(2 pi R) = (nhe)/(4 pi^(2) mR^(2))` Magnetic MOMENT for a current loop can be written as m ` = IA` `mu = I pi R^(2) = (nhe)/(4 pi^(2) mR^(2)) pi R^(2) = (nhe)/(4 pi m)` |
|