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An electron in a hydrogen atom makes a transition n_(l) rarr n_(2), where n_(1) and n_(2) are principal quantum numbers of the states. Assume the Bohr's model to be valid. The time period of the electron in the initial state is eight times to that of final state. What is ratio of n_(2)//n_(2) |
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Answer» Solution :Since, T `prop N^(3)` `therefore (T_(1))/(T_(2)) = (n_(1)^(3))/(n_(2)^(3)) " As" T_(1) = 8T_(2), ((n_(1))/(n_(2)))^(3) = 8 " (or)" n_(2) = 2n_(2)`. Thus the POSSIBLE values of `n_(1) and n_(2)` are `n_(1) = 2, n_(2) = 1 , n_(1) = 4 , n_(2) = 2 , n_(1) = 6, n_(2) = 3 `, and so on ..... |
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