An electron in hydrogen atom after absorbing an energy photo jumps from energy state `n_(1)` to `n_(2)`. Then it returns to ground state after emitting six different wavelength in emission spectrum. The energy of emitted photons is either equal, to less than or greater than the absorbed photons . then `n_(1)` and `n_(2)`A. `n_(2)=4,n_(1)=3`B. `n_(2)=5, n_(2)=3`C. `n_(2)=4, n_(1)=2`D. `n_(2)=4, n_(1)=1`

An electron in hydrogen atom after absorbing an energy photo jumps fro

1.	An electron in hydrogen atom after absorbing an energy photo jumps from energy state `n_(1)` to `n_(2)`. Then it returns to ground state after emitting six different wavelength in emission spectrum. The energy of emitted photons is either equal, to less than or greater than the absorbed photons . then `n_(1)` and `n_(2)`A. `n_(2)=4,n_(1)=3`B. `n_(2)=5, n_(2)=3`C. `n_(2)=4, n_(1)=2`D. `n_(2)=4, n_(1)=1`
Answer» Correct Answer - C From `n_(2)=4` , six lines are obtained in emission spectrum Now:`E_(4)_(1)=E_("obserbed")` ` E_(4)to3 lt E_("absorbed")` and `E_(4)_(-1)E_(3)_(1),E_(2-1) gt E_("absorbed")` Hence , `n-(1) =2` and `n_(2)=4`

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