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An electron is accelerated in an electric field of `40V cm^(-1)`. If `e//m` of electron is `1.76 xx10^(11) Ckg^(-1)` , then its acceleration isA. `14.0xx10^(14)ms^(2)`B. `14.0xx10^(10)ms^(-2)`C. `7.0xx10^(10)ms^(-2)`D. `7.04xx10^(14)ms^(-2)` |
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Answer» Correct Answer - D `a=(Ee)/m` |
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