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An electron is accelerated through a potential difference of 100 volts. What is the de-Broglie wavelength associated with it ? To which part of the electromagnetic spectrum does this value of wavelength correspond ? |
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Answer» SOLUTION :The ACCELERATING VOLTAGE `V=100V` `therefore`de-Broglie wavelength of ELECTRON `lamda=(h)/(sqrt(2emV))=(6.626xx10^(-34))/(sqrt(2xx1.602xx10^(-19)xx9.1xx10^(-31)xx100))` `=1.227xx10^(-10)m or 1.227Å` The value of de-Broglie wavelength corresponds to X-rays PART of the electromagnetic spectrum. |
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