1.

An electron is accelerated through a potential difference of 64volts. What is the de-broglie wavelength associated with it? To which part of the electromagnetic spectrum does this value of wavelength correspond?

Answer» Correct Answer - `1.53Å`, x-rays`
`lambda=(12.27Å)/(sqrt(64))=1.53Å`
This wavelength belong to x-rays.


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