An electron is accelerated to a potential of 200 V and acquires a velocity of 8.4xx10^(6)ms^(-1). The e/m is:

An electron is accelerated to a potential of 200 V and acquires a velo

1.	An electron is accelerated to a potential of 200 V and acquires a velocity of 8.4xx10^(6)ms^(-1). The e/m is:
Answer» `1.76xx10^(9)C//kg` `1.76xx10^(10)C//kg` `1.76xx10^(11)C//kg` `1.76xx10^(12)C//kg` Solution :`e//m=(v^(2))/(2V)=(84xx10^(6)xx84xx10^(6))/(2xx200)` `=1*764xx10^(11)XXC kg^(-1)`

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An electron is accelerated to a potential of 200 V and acquires a velocity of 8.4xx10^(6)ms^(-1). The e/m is:

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