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An electron is at a distance of 10 m from a charge of 10c.Its total energy is 15.6xx10^(-10) J.Its de-Broglie wavelength at this point is…….. .(h=6.625xx10^(-34))J.s ,m_(e)=9.1xx10^(-31)kg, K=9xx10^(9)SI |
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Answer» Solution :Potential energy of an electron ,`U=-(kq(e))/(R )` `therefore U=-(9xx10^(9)xx10xx1.6xx10^(-19))/(10)` `therefore U=-14.4xx10^(-10)J` Now total energy E=Kinetic energy K+potential energy U `therefore`K=E-U `=15.6xx10^(-10)+14.4xx10^(-10)` `therefore K=30xx10^(-10)J` But K`=(p^(2))/(2m_(e))` `therefore p=SQRT(2km_(e))` `lambda=(h)/(sqrt(2km_(e)))=(6.625xx10^(-34))/(sqrt(2xx30xx10^(-10)xx9.1xx10^(-31)))` `therefore lambda=8.97xx10^(-15)m` |
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