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An electron is moving at 10^(6) ms^(-1) in a direction parallel to a current of 5A flowing through an infinitely long straight wire , separated by a perpendicular distance of 10 cm in air. Calculate the magnitude of the force experienced by the electron. |
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Answer» Solution :Magnetic field of the straight wire carrying a current of 2A, at a DISTANCE of 10cm or 0.1m from it is `B = (mu_(0) I)/(2pi r) = (4pi xx 10^(-7)xx 5)/(2i xx 0.1) = 10^(-5)` T this field ACTS perpendicular to the direction of the electron . So magnetic FORCE on th electron is F = qv B sin `90^(@) = 1.6 xx 10^(-19) xx 10^(6) xx 10^(-5) xx 1` F = `1.6 xx 10^(-18)` N |
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