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An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57xx10^(-2)T. If the value of e/m is 1.76xx10^(11)C/(kg), the frequency of revolution of the electron is |
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Answer» 62.8 MHz `thereforev=(BER)/m` `thereforeromega=(Ber)/m""[becausev=romega]` `thereforeomega=(Be)/m` `therefore2pif=(Be)/m""[becauseomega=2pif]` `thereforef=B/(2pi)xxe/m=(3.57xx10^(-2)xx1.76xx10^(11))/(2xx3.14)` `thereforef=10^(9)Hz=1GHz` |
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