1.

An electron is moving in an orbit of a hydrogen atom from which there can be a maximum of six transition. An electron is moving in an orbit of another hydrogen atom from which there can be a maximum of three transition. The ratio of the velocities of the electron in these two orbits is :

Answer»

`(1)/(2)`
`(2)/(1)`
`(5)/(4)`
`(3)/(4)`

Solution :Number of spectral lines obtained due to TRANSITION of electrons from nth orbit to lower orbit is,
`N=(n(n-1))/(2)`
I Case `6=(n_(1)(n_(1)-1))/(2)`
`rArr n_(1)=4`
II Case `e=(n_(2)(n_(2)-1))/(2)`
`rArr n_(2)=3`
VELOCITY of electron in hydrogen atom in nth orbit
`v_(n) prop (1)/(n)`
`(v_(n))/(v_(n))=(n_(2))/(n_(1))`
`rArr (v_(6))/(v_(3))=(3)/(4)`


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