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An electron is moving with a velocity (2 hat(i) + 2hat(j))m//s is an electric field of intensity vec(E )= hat(i) + 2hat(j)- 8 hat(k) V//m and a magnetic field of vec(B)= (2 hat(j) + 3hat(k)) tesla. The magnitude of force on the electron is |
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Answer» `14.4 xx 10^(-19)N` Electric field `= vec(E )= hat(i) + 2hat(j) - 8hat(k) V m^(-1)` Magnetic field `= vec(B) = 2hat(j) + 3HAT(k) T` `:.` The Lorentz FORCE is `vec(F) = q (vec(E ) + vec(v) xx vec(B))` `=(-1.6 xx 10^(-19)) [hat(i) + 2hat(j) -8hat(k) + (2hat(i) + 2hat(j)) xx (2hat(j) + 3hat(k))]` `=(-1.6 xx 10^(-19)) [hat(i) + 2hat(j) - 8hat(k) + 4hat(k) - 6hat(j) + 6hat(i)]` `=(-1.6 xx 10^(-19)) [7 hat(i) - 4hat(j) - 4hat(k)]` `|vec(F)| = 1.6 xx 10^(-19) xx 9 = 14.4 xx 10^(-19)N` |
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