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An electron is revolving around the nucleus with a constant speed of 2.2 xx 10^(8) m//s. Find the de-Broglie wavelength associated with it. |
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Answer» Solution :`lambda=(H)/(mv)` `=(6.63xx10^(-34))/(9.1xx10^(-31)xx2.2xx10^(8))` `=3.31xx10^(-12)m` |
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